A mathe exercise:
We are now going to find the starting amount and the final amount.
Formula:
K = K_{0} ∙ (1 + r)^{n}
r = rate
K_{0} = starting amount
K = final amount
n = number of periods
Starting amount 
Rate 
Number of periods 
Final amount 
117,00 
11 % 
5 

1000,00 
5 % 
17 


6 % 
4 
2765,88 

17,75 % 
10 
5789,76 
We have found the solution :
K=KO*(1+r)n
K=117.00*(1+11%)*5= 649.35
K=1000.00*(1+5%)*17 = 17850
2765.88 = KO*(1+6%)*4
KO = 652.33
5789.76 = KO*(1+17.75%)*10
KO = 491.7
Thank you
Bye Bye
your answer to the exercise is wrong, because the rate should be in decimal.
So 6% is 0,06.
Try doing that with all the calculations 🙂
Oups !! We are not very gifted. We are a little bit tired so the rigth answer is
K= 117.00*(1+0.11)*5 = 649.35 ?
K= 1000.00*(1+0.05)*17 = 17850 ?!
2765.88 = KO*(1+0.06)*4
KO =652.33 ?!!
5789.76 = KO*(1+0.1775)*10
KO = 491.7 ??!!
We don’t understand we found exactly the same answer. Where is the problem ?
okay, now I found the mistake.
You aren’t supose to multiply with n. You need to exalt it in n.
That is why your results are the same as mine.
We don’t understand. We must multiply to the power n ?
Now we try AGAIN using to the power n :
K = 117.00*(1+0.11)^5 = 197.15
K = 1000.00*(1+0.05)^17 = 2292.01
2765.88 = KO*(1+0.06)^4
KO = 2190.83
5789.76 = KO*(1+0.1775)^10
KO = 1129.92
It’s more logical isn’t it ?
I hope it’s the good answer
I won’t restart all the calcul.
now it is right 🙂 good
Cool !! We have save our honnor. What is our mark ?
You must give us a good mark because you don’t give all the information. 😉