Hello, this is the answer of the first question of the Eiffel tower's problem. We can't do the others questions because the picture is too little. Can you send a bigger please ? Thank you. ABC is isoscele in C. We call [AH] the leaving height of A. [AH] divide BA in two equal segments : CH= c×1/2= 97,5×1/2= 48,75 m [AH] is perpendicular to (AB) so AHC is a right-angle triangle. We can use the propriety of Pythagore : HC² + AH² = CA² 48,5² + 800² = CA² 2376,2 + 640000 = CA² 642376,2 = CA² The 642376,2's square root is equal to 801,5 CA = b = a = 801,5m Now, we can use trigonometry: cos(Ĉ) = 800/801,5 Ĉ = cos-1×800/801,5 ≈ 3,5° Cos(Â) = 48,5/801,5 Â = cos-1×48,5/801,5 ≈ 86,5°
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– 13 June 2009
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